修复存款不提示的问题
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@ -11,7 +11,7 @@ from src.core.util import get_curr_day, get_first_day_month
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from src.entity.account import Account
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from src.entity.member import (MemberList, async_get_member_detail_by_name,
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get_member_by_name, get_member_list)
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from src.entity.user import User, get_user_by_telegram_id
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from src.entity.user import User, get_user_by_telegram_id, get_user_by_username_and_password
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@dataclass
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@ -51,37 +51,53 @@ def get_pay_record(account: Account):
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return [PayRecord(**item) for item in api_response.data['list']]
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from concurrent.futures import ThreadPoolExecutor, as_completed
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from datetime import datetime
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def get_latest_deposit_user(account: Account, count: int):
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logger.info(f'Getting latest deposit user for account: {account.name} and count: {count}')
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pay_record_list = get_pay_record(account)
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# 提取所有用户名
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names = []
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seen = set()
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# 提取所有用户名,并确保在指定时间内
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now = datetime.now()
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for item in pay_record_list:
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name = item.name
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if name not in seen and util.get_difference(item.createdAt, now) < 7200:
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names.append(name)
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seen.add(name)
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logger.debug(f"获取到{len(names)}个成功存款人数")
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# 开启多线程 根据用户名查询所有数据
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with ThreadPoolExecutor(max_workers=len(names)) as executor:
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futures = [executor.submit(get_member_by_name, account, name) for name in names]
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try:
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results = [future.result() for future in futures]
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except Exception as e:
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logger.debug(f'查询失败:{e}')
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sorted_members = sorted(results, key=lambda member_detail: member_detail.get_first_pay_datetime(), reverse=True)
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# 截取前n个
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details = sorted_members[:count]
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record_dict = {record.createdAt: record.scoreAmount for record in pay_record_list}
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member_details = []
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for detail in details:
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if detail.firstPayAt in record_dict:
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detail.deposit = record_dict[detail.firstPayAt]
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member_details.append(detail)
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logger.info(f'Finished getting latest deposit user for account: {account.name} and count: {count}')
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return member_details
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unique_names_within_time = {
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item.name for item in pay_record_list if util.get_difference(item.createdAt, now) < 7200
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}
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logger.debug(f"获取到{len(unique_names_within_time)}个成功存款人数")
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# 开启多线程根据用户名查询所有数据
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results = []
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with ThreadPoolExecutor(max_workers=min(len(unique_names_within_time), 20)) as executor: # 限制最大工作线程数
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futures = [executor.submit(get_member_by_name, account, name) for name in unique_names_within_time]
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for future in as_completed(futures):
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try:
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result = future.result()
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results.append(result)
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except Exception as e:
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logger.debug(f'查询失败:{e}')
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# 筛选出有有效结果的成员,并按首次付款时间降序排序
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valid_results = [result for result in results if result is not None]
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sorted_members = sorted(valid_results, key=lambda member_detail: member_detail.get_first_pay_datetime(),
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reverse=True)
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# 截取前n个
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selected_members = sorted_members[:count]
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# 构建时间和金额的映射字典
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record_dict = {record.createdAt: record.scoreAmount for record in pay_record_list}
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member_details = []
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for detail in selected_members:
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# 检查 detail.firstPayAt 是否在 record_dict 中,避免 KeyError
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if detail.firstPayAt in record_dict:
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detail.deposit = record_dict[detail.firstPayAt]
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member_details.append(detail)
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logger.info(f'Finished getting latest deposit user for account: {account.name} and count: {count}')
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return member_details
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# 根据用户查询最新存款信息
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@ -227,3 +243,10 @@ def get_pay_failed_by_telegram_id(telegram_id: int) -> Optional[str]:
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logger.info(text)
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return text
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if __name__ == '__main__':
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deposit_results = '\n'.join(
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[f"用户: `{member.name}`, 首存金额: *{member.deposit}*" for member in
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get_latest_deposit_user(get_user_by_username_and_password('zayac', 'password').accounts[0], 1)])
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print(deposit_results)
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@ -549,3 +549,4 @@ class Application(QMainWindow):
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def copy_to_clipboard(text):
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clipboard = QApplication.clipboard()
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clipboard.setText(text)
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